CHEMISTRY 1.pmd

Be- pg PnÃm ] m-b v \ndhv ]T\ klmbn ck-x{ w Std : X X m-dm- n-b-xv:þ 1.P. Suresh Babu Govt. Model HSS, Ambalapuzha 2.P.V. Babu Abraham, SNHSS Sreekanteswaram, Poochakal, Cherthala. 3.Shaji Joseph Holy Family HSS Cherthala. 4.Sreekumar Sarma S., GSVHSS, Kudassanadu

* {Zh-y- nsâ {][m\ Ah-Ø-IÄ * hmx-i- nsâ hym-]vxhpw aà±hpw * Un^-yq-j³ * hmxi aà±w, A -co- -aà±w * t_mbnâ \nbaw * NmÄkv \nbaw * A_vk-e-yq«v kotdm * kwtbm-pnx hmxikahmiyw * Ahm-Kmt{Um \nbaw Chapter 1 hmx-im-hø {][m-\m-i-b-mä * hmxi \nbaw {]tbm-p-\-s -Sp- n-bn-cn- p taj-e-iä

amxri tnmz-y- Ä: hmx-im-hø Q1. Jcw, {Zmh-Iw, hmxiw F o Ah-Ø-I-fn X m-{x-iä X½n-ep-ff AI-ew, BIÀjW _ew F nh F s\ hy-x-ym-k-s -«n-cn- p p? Q2. sfkv DcpIn Pe-am-Ip- -Xpw, Pew Xnf v \ocm-hn-bm-ip- Xpw \n Ä I-n-«p-v F -s\-bmwv Cu AhØm ]cn-hà \w \S- p- Xv? Q3. \\ª Npcp«n Iq«n-bn«XpWn-bmtWm \nhà n-bn«xpwn-bmtwm thk- nâ DW p- -Xv. F psim-v? Q4. o o oooooooooo o o o o o ooooooooooo o o o o ooooooooooo o o o o o o Jcw {ZmhIw hmxiw aq p ]m{x- -fn-embn Jcw, {Zmh-Iw, hmxiw F o Ah-Ø-I-fn-ep-ff ]ZmÀ - Ä AS p h n-cn- p- p. aq p ]m{x- -fp-ssbpw AS v \o w snbvxmâ GXm-bn-cn pw DS³ ]pd-t v hym-]n- pi? F m-bn-cn pw ImcWw? Q5. Hcp apdn-bnâ Hcp Nµ-\- ncn I n p hbv p-i. ]pibpw KÔhpw aäp `mk- -fntebv v hym-]n- p- p-t-m? F m-bn-cn pw ImcWw? Q6. Hcp knen---dnâ AS- n-cn- p hmx-i- nsâ Nn{Xo-I-c-W-amWv \ÂIn-bn-cn- p- -Xv. Nn{X- nâ ]nì B, C F o Øm\- -fn-te v \o n-bm-ep--m-ip amä- Ä Fs - Ãm-am-bn-cn pw

Q7. Aev]w am{xw hmbp \nd _eq Hcp Kvfmkv t_m«n-enâ h n-cn- p p (1) Cu t_m«n-te v iàn-bmbn DuXp-I. (2) Cu t_m«n-enâ \n pw hmbp ]pd-t v hens -Sp- p-i. Cu c-p {]hà -\- -fnepw \n -fpss \nco- Ww Ipdn- p-i. ImcWw hy-à-am- pi? hym]vxxq8. Hcp hmxi \nb-a-hp-ambn _Ô-s Hcp {Km^m-Wn-Xv. GXp hmxi \nbaw? hym]vxx CXnsâ KWnX cq]w Fgp-XpI? aà±w (P) (V) Q9. Imem-hØm \nco- -W- n-\p-]-tbm-kn- p _eq-wp-iä kap{z \nc- nâ \n pw Dbcpw-tXmdpw AXnsâ hen w IqSp- p. hni-zo-i-cn- pi? _o -dnâ FSp Pe- nâ Hcp sndnb Ip n Xe Iogmbn Ivfm¼p snbvxp sh -Xn\p tijw _o À NqSm- p-i. F mwp \n -fpss \nco- -Ww. CXv GXp hmxi \nba-hp-ambn _Ô-s -«n-cn- p- p. CXnsâ KWnX cq]w Fgp-XpI? Hcp

Hcp hmx-i- n\v F n-t -cm³ Ign-bp Gähpw Xmgv Xm]-\n-e-bp-ambn _Ô-s «{Km^mWv \ÂIn-bn-cn- p- -Xv. GXmWv B Xm]\ne? CXv siâhn³ kvsibn-en-em- nbmâ F{X-bmIpw? Q12. t_mbnâ \nbahpw NmÄkv \nb-ahpw kwtbm-pn- n- mâ AXv kwtbm-pnx hmxi \nb-a-amipw CXnsâ hmxi ka-hm-iyw Fgp-XpI? Q13. V n F Xv GXp \nb-a-hp-ambn _Ô-s -«n-cn- p- p. CXnsâ \nàæ-n\w Fgp-XpI? Q14. 273 K Xm]-\n-e-bn 320 an.-en. ss\{s-p³ hmxiw \nd knen-dnâ A\p-`-h-s -Sp aà±w 1 atm. BWv. Xm]-\ne 27 0 c Dw aà±w 0.5 atm Bbn amdn-bmâ ss\{s-p³ hmx-i- nsâ hym]vxw F{X-bmIpw? Q15. hmxi \nb-a- Ä {]tbm-p\s Sp- n-bn-«p-ff hnhn[ taj-e-iä Gh? (Answer Key) 1. Jcw þ X m-{x-iä hfsc ASp p ØnXn sn p- p. þ BIÀjW _ew hfsc IqSp-X {Zmh-Iw þ X m{x-iä Jc hkvxp-hn-t\- mä AI p ØnXn sn p- p. hmx-iw þ BIÀjW _ew Jc hkvxp-hn-t\ mä Ipdhv þ X\vam{X-IÄ hfsc AI p ØnXn sn p- p. þ BIÀjW _ew hfsc Ipdhv 2. sfkv Pe-am-Ip-t¼mÄ þ Xm]w kzo-i-cn- p- p. X m-{x-iä AI-ep- p (KXn-tImÀÖw IqSp- p) AhØ amdp- p. Pew \ocm-hn-bm-ip-t¼mä þ Xm]w kzo-i-cn- p p þ KXn-tImÀÖw hà²n- v X m- {X-IÄ AI-ep- p. - 3. \nhà n-bn«xpwn þ _mjv]o-i-cw \nc v IqSp-X 4. hmxiw þ X m-{x-iä v Ne\ kzm-x-{ yw IqSp-X þ Un^-yq-j³ 5 Un^-yq-j³ 6. B bnte v amänbmâ aà±w IqSp- p. C bnte v amän-bmâ ho-pw aà±w IqSpw (hm-xiw {Zmh-I-am-Imw) 7. 1) _eq-wnsâ hen w Ipd-bp- p. 2) _eq-wnsâ hen w IqSp- p. t_m«n-en-\p-f-fnse hmxi aà±- n-\-\p-k-cn v _eq-wnsâ hen w amdp- p.

8. t_mbnâ \nbaw (P 1/v) 9. Dbcw IqSpw txmdpw A -co aà±w Ipd-bp- p. 10. hmbp Ipan-f-IÄ D-m-Ip- Xp ImWmw NmÄkv \nbaw 11. þ273 w C ; OK 12. P 1 V 1 = P 2 V 2 T 1 T 1 13. Ahm-Kmt{Um \nbaw þ \nàæ-n\w 14. P 1 V 1 = P 2 V 2 i.e. V 2 = 1x320x300 = 703.29 ml T 1 T 1 273x0.5 15. hy-hkmbw, Imem-hØ {]h-n-\w, Btcm-Ky taje, \nxy PohnXw Chapter 2 cmk-{]-hà -\- fpw tamä k -ev]\hpw {][m-\m-i-b- Ä * cmk-{]-hà -\- -fpss thkx * cmk-{]-hà \ thk-xsb kzm-[o-\n- p LS-I- Ä * {Kmw Atäm-anI amkv, {Kmw tamfn-i-yp-emà amkv * tamä k ev]\w * Ahm-Kmt{Um kwjy * tamfmà hym]vxw * tamfmà emb\n * simfo-j³ Xnbdn * Ahm-Kmt{Um \nbaw * tamä k -ev]\hpw kao-irx cmk ka-hm-i-yhpw amxrim tnmz-y- Ä cmk {]hà -\- fpw tamä k -ev]\hpw Q1. cmk-{]-hà -\- nsâ thk-xsb kzm-[o-\n- p LS-I- Ä Gh? Q2. c-p ssì-yq-_p-i-fnâ Xpey Af-hn t\à n HCL FSp- p-i. Htc hen- -ap-ff c-p amà_nä Ij-W- Ä FSp- p-i. Hcp amà_nä IjWw Hcp ssì-yq-_nse Bkn-Un CSp-I. ASp amà_nä IjWw s]msn v atä ssì-yq-_nse Bkn-Un CSp-I. \nco- n- p-i.

1) Ipan-f-I-fmbn ]pd p hcp hmx-i-taxv? 2) GXn-emWv {]hà \w thk nâ \S- p- Xv? 3). F p-sim--mwv {]hà \w thk- nâ \S- -Xv. Q3. c-p _o -dp-i-fnâ t\à n tkmunbw Utbm-kÄt^äv emb\nfsp- p-i. Hcp _o -dnse emb\n NqSm- p-i. c-n-te pw Xpey Af-hn t\à n HCl tnà p-i. 1. F mwv \n Ä \nco- n- p- -Xv. 2. cmk-{]-hà \w GXp _o -dn-emwv thk- nâ \S- p- -Xv. 3. cmk-{]-hà \ ^e-ambn cq]w simåp ]ZmÀ w GXm-Wv. Q4. c-p ssì-yq-_p-i-fnâ ssl{u-p³ s]tdm-ivsskuv emb\n FSp- p-i. H n-te v Aev]w amwk-\o-kv-þ-u-tbm-ivsskuv tnà pi. 1) F mwv \nco- Ww 2) ]pd-t v hcp hmx-i- n-te v Hcp Fcn-bp Nµ-\- ncn ImWn- p-i. F mwp \nco- Ww? 3) GXmWv hmxiw? 4) \nk-a-\- n\p ImcWw? Q5. ssl{u-p³ s]tdm-ivssk-unsâ hnl-s\ thkx Ipd- p-hm³ D]-tbm-Kn- p ]ZmÀ w? Q6. Hcp Kvfmkv ]vtfän\p api-fnâ Hcp sndnb sagp-ip-xncn I n p hbv p-i. CXns\ Hcp Kvfmkv Sw_vfÀ sim-v aqsn shbv p-i. F p sim-mwv sagp-ip-xncn AWªp t]mbxv? Q7. tamä \nàæ-nn-bv mtam? Q8. {Kmw Atäm-anIv amkv (GAM) {Kmw tamfn-i-yp-eà amkv (GMM) Ch F mwv? Q9. 1 g ssl{u-p-\nâ F{X Bä- Ä? 4 g loen-b- nâ F{X Bä- Ä? Q10. kä^-yq-cniv Akn-Unsâ ( H2SO4 ) tamfn-i-yp-emà amkv I-p-]n-Sn- pi? (H=1, S=32, O=16) Q11. CaCO3, CaCl2, Ca(OH)2 F nh ImÂk-y- nsâ aq p kwbp-à- Ä BWv. Ch Hmtcm pw F{X {Kmw hoxw FSp- m-emwv X m{xifpss F w Xpe-y-am-bn-cn- pi? (kqn-\: Atäm-an-Iv amkv. Ca = 40, Cl = 35.5, O = 16, H = 1) Q12. STP  ØnXn sn p 224L CO2 - F{X tamä X m-{x-iä Ds- v I-p ]nsn- pi? Q13. CH4+2O2 CO2 + 2H2O aoty³ hmxiw hmbp-hnâ I p- -Xnsâ kao-irx cmk ka-hm-i-y-am-wn-xv. 160g aoty³ hmbp-hnâ ]qà -ambn I m³ F{X {Kmw HmIvkn-P³ th-n hcpw? Q14. tamfmà emb\n F m-sw v hni-zo-i-cn- mtam? Q15. A,B,C F o timf- -fnse _Ôw icn-bm n Fgp-Xp-I.

A B C a) 5 tamä H2SO4 16g 224L STP  490g b) 440g CO2 H 2 O 2 sâ hnl-s\ DÄt{]-cIw thk-xsb kzm-[o-\n- p- p. c) H 3 PO 4 5x6.022x10 23 1GMM d) CH 4 10 mol 490 g kqn-\: Atäm-anI `mcw ( H =1, C=12, S = 32, O = 16, P = 31) Answer Key 1. A`n-Im-c- nsâ kz-`mhw, KmV-X, Dujvam-hv, aà±w, {]Xe hnkvxoà w, DÄt{]-c-I- nsâ km n-²yw 2. 1) CO2 2) -amà_nä s]msn- n«ssì-yq-_nâ 3) {]Xe hnkvxoà w þ cmk {]hà \ \nc v hà²n- n- p- p. 3. 1) NqSm- n-b _o -dnâ \nd-amäw kw`-hn- p- p. 2) NqSm- nb _o -dnâ 3) kä^à - 4. 1) amwk-\okv UtbmIvsskUv tnà ssì-yq-_nâ cmk-{]-hà \w thk- nâ \S- p- p. 2) Nµ-\- ncn thk- nâ `wkn-bmbn I p- p. 3. HmIvkn-P³ 4. amwk-\okv Utbm-IvsskUv DÄt{]-c-I-ambn {]hà n v H 2 O 2 hnl-sn v thk nâ O 2 D-m p- p. 5. t^mkvt^m-dn mkn-uv. 6. mêv Sw»-dn-\p-Ånse hmbp sagp-ip-xncn I m³ th-n D]-tbm-Kn p Xocp- Xp sim-v. 7. tamäþ \nàæ-n\w 8. GAM, GMM - \nàæ-n-\w. 9. 1 tamä (6.022 10 23 ) 10. H 2 SO 4 = (1X)+32+(16X4) = 98 11. CaCO 3 = 40+12+(16x3) = 40+12+48 = 100 g CaCl 2 = 40+ (35.5x2) = 40+71 = 111g Ca(OH) 2 + 40+(17x2) = 40+34 = 74g 100 g CaCo 3 = 111g CaCl 2 = 74g Ca(OH) 2 = 1 Mol

12. tamfp-i-fpss F w = 224L 22.4 = 10 13. 640 g 14. tamfmà emb\n þ \nàæ-n\w 15. A B C 5 Mol H 2 SO 4-5x6.022x10 23-490 g 440 g Cl 2-10 Mol - 224L H 3 PO 4 þ H2O2hnL-S\ thk-xsb kzm[o-\n- p- p. þ DÂt{]-cIw CH4-16g - 1GMM